WebApr 8, 2024 · Partially decidable or Semi-Decidable Language -– A decision problem P is said to be semi-decidable (i.e., have a semi-algorithm) if the language L of all yes … Web1 is decidable. This language is ambiguous. 4.2 Some non-algebraic languages decided in -CL-PRec Languages a n 1 a n 2 a n 1. Since intersection of decidable languages is decidable, the language a n 1 a n 2 a n 1 = a n 1 a n 2 a m 1 \ a n 1 a m 2 a m 1 is decidable. This language is not alge-braic. Similarly, it is possible to prove that the ...
Relationship between context-free/decidable languages and NP
WebAnswer (1 of 4): As others have mentioned, the answer is obviously No if P=NP, and not-obviously Yes if P\neqNP, thanks to Ladner’s Theorem. What is perhaps more … WebThe complement of every Turing decidable language is Turing decidable. II. There exists some language which is in NP but is not Turing decidable. III. If L is a language in NP, L is Turing decidable. Which of the above statements is/are true? This question was previously asked in. GATE CS 2015 Official Paper: Shift 2 Attempt Online. blackbeard 2nd devil fruit
Decision problem - Wikipedia
WebHey folks, "𝗛𝗲𝗹𝗹𝗼 𝗪𝗼𝗿𝗹𝗱" is a starting point of every language you learn. So, Let's find out "𝗛𝗲𝗹𝗹𝗼 𝗪𝗼𝗿𝗹𝗱" in 9 different programming… WebJan 5, 2016 · This first step enables us to prove our main result: one can decide whether the iteration of a given regular language of MSCs is reg- ular if, and only if, the Star Problem in trace monoids is decidable too. This relationship justifies the restriction to strongly connected HMSCs which de- scribe all regular finitely generated languages. WebSep 14, 2010 · The halting problem is a classical example of NP-hard but not in NP problem; it can't be in NP since it's not even decidable, and it's NP-hard since given any NP-language L and an NP machine M for it, then the reduction from L to halting problem goes like this: Reduce the input x to the input ( M ′, x), where M ′ is a machine that runs … blackbeard 6 star astd